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Friday, October 15, 2010

About Where establishment can a 14 year old work

Where establishment can a 14 year old work?
Im looking for a place in Henderson Las Vegas that hires at fourteen. other than that the only requirement is it is a job such as a bus boy, cashier, bagger, waiter, etc... Basically good starter job.
Small Business - 3 Answers
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1 :
From what I remember, very few places would hire anyone under 21. If the place has slot machines, you have to have a sheriff's card, and you can't get one of those until you're 21. The laws might have changed since I worked there, but I doubt it. Vegas is a gambling town, and there's not much to do there if you're under 21.
2 :
well you cannot get job until you are of age (16) so no where. deal with it
3 :
Check your local restaurants, and McDonalds, I heard that they hire at 14. Ignore what the other people say about not being able to get a job until you're 16. You may be able to get a job, but you won't necessarily get paid minimum wage.
4 :
sweat shop.


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    Wednesday, October 13, 2010

    About How do you use the henderson-hasselbalch equation to calculate changes in pHHow do you use the henderson-hasselbalch equation to calculate changes in pHHow do you use the henderson-hasselbalch equation to calculate changes in pH

    How do you use the henderson-hasselbalch equation to calculate changes in pH?
    im trying to work out the answer to this but i keep getting stuck..can you please explain it in a really *simple* way? The pH of a buffer solution made up of acetic acid (0.100 mol L-1) and sodium acetate (0.100 mol L-1) is 4.76. How much will the pH of this buffer change if 100 mL of 0.100 mol L-1 HCl is added to 1.00 L of the buffer solution?
    Chemistry - 1 Answers
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    1 :
    The added acid will protonate the acetate, thus lowering its concentration. The acetic acid concentration will rise. We needed to determine the moles of Ac- and HAc present before adding the HCl. Both are 0.1 mole. You may verify this. we added (0.1 L) (0.1 mol/L) = 0.01 mole of HCl. Therefore the HAc goes from 0.1 mol to 0.11 mole and the Ac- goes 0.1 mol to 0.09 mol. Notice that the total volume rises from 1 L to 1.1 liter. This will create new molarities, but I will ignore the molarity calculation. This is because the ratio portion of the H-H will work just fine with the mole amounts. pH = 4.76 + log (0.09/0.11) gives the answer.


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