How to predict pH of buffer solution - Henderson-hasselbalch equation? An acetate buffer was prepared by adding 25mL of 1M acetic acid to 3.418g of sodium acetate trihydrate. We are asked to predict the pH of this buffer solution using the Henderson-Hasselbalch equation. I'm not sure how to work out the pKa that we have to find to work out the pH using the equation pH=pKa + log([conj. base]/[acid]) I'd appreciate any help, thanks in advance1 Chemistry - 2 Answers Random Answers, Critics, Comments, Opinions : 1 : pKa = -log Ka the Ka of acetic acid should be on the appendix of your textbook or you can look for it online. pKa of acetate is 4.76 at 25 C. 2 : moles CH3COONa *3 H2O = 3.418 g/ 136.09 g/mol=0.0251 concentration acetic acid = 0.0251 mol/ 0.025 L= 1.00 M pKa of acetic acid = 4.74 pH = pKa + log [CH3COO-]/ [CH3COOH] = 4.76 + log 1.00 / 1 = 4.74 Read more other entries : |
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